thanks for your reply.
[1]
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that is a good pointI overlooked that. Nevertheless, the effective strain rate would be different for 3:
All three use the following formula for the strain rate:
gamma_dot=gamma0_dot*((lambda_b^p)-1)^c*(tau_b/tau_base)^m
but tau_b for 3 (BB 1998) is different then tau_b for 1 and 2 (BB 01, Bergstroem). So in my view that would result in two different gamma_dot (one for 1,2 and one for 3).
[2]
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that would be great if you could get back to me on that one. Thanks!
[3]
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I do. I was just trying to clarify that I do not have to multiply B_b^p with (J_b^p)^(-2/3), like it is done for the chain stretch in T_A [lambda^(*): from B_(*)=J^(-2/3)*B] and in T_B [lambda_b^(e*): from B_b^(e*) =(J_b^e)^(-2/3)* B_b^(e)] but I just realized that J_b^p=1....or is it is this only in the very beginning when lambda+0
Thanks



I overlooked that. Nevertheless, the effective strain rate would be different for 3:
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